![]() ![]() *Pricing in countries may vary and actual charges may be converted to your local currency depending on the country of residence. Adapt your files routine with all-in-one solution. The file manager built-in allows to open compressed files, browse them and view content of different extensions. zip files in the current working directory are files you want to do this for, you can get ziplist above via: list.files(pattern = ".zip") %>% as.Zip Extractor & RAR Opener App here to assist you with anything you need to unarchive or compress files. # Example of multiple zip directory paths in a list If you had multiple zipped directories with nested directories similar to main_dir, you could just put their paths in a list and apply the function to each element of the list. ![]() # Unzip the highest level directory available, get all of the. Given this structure, we can get the paths to all of the directories within the highest level directory ( main_dir) using unzip(list = TRUE) since we know the name of the single zipped directory containing all of these additional zipped sub-directories. ![]() # Manually zip example_dir1 and example_dir2, then zip main_dir at this point. # then the main (top) directory, so I manually zipped them below. # NOTE: I was having issues with using `zip()` to zip each directory Write.csv(ame(x = "foo"), file = "main_dir/example_dir2/example_file2.csv") Write.csv(ame(x = 5), file = "main_dir/example_dir1/example_subdir/example_subdirfile.csv") Write.csv(ame(x = 5), file = "main_dir/example_dir1/example_file.csv")ĭir.create("main_dir/example_dir1/example_subdir") # Example directory with 1 file and a subdirectory with 1 file zip file that contains multiple zipped directories, which may contain unzipped files and/or sub-directoris. Let's create an simple set of directories/files that are representative of your own. ![]()
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